Question

1) The smallest angle of a triangle whose angles are in the ratio
2:4:3 is​

Answer 1

Step-by-step explanation:

Given, the ratio of angles of a triangle is 2 : 4 : 3.

Let the angles of a triangle be ∠A, ∠B and ∠C.

∠A = 2x, ∠B = 4x

∠C = 3x , ∠A+∠B+ ∠C= 180°

[sum of all the angles of a triangle is 180°]

2x + 4x + 3x = 180°

9x = 180°

x=180°/9 =20°

∠A=2x=2 x 20° = 40°

∠B = 4x = 4 x 20° = 80°

∠C = 3x = 3 x 20° = 60°

Hence, the smallest angle of a triangle is 40°.

hope it helpful

Answer 2

Answer:

40°

Step-by-step explanation:

let the angels be 2x,4x,3x respectively

2x+4x+3x=180°(Anglesum property)

9x=180°

x=20°

Therefore smallest Angle =2×20°=40°

Hope it helps you