Question

1) The son's age is one-third that of his father. Five years
ago father's age was 4 times as old as his son. Find their
present age.​

Answer 1

Step-by-step explanation:

Given:

Son's age is ⅓ that of his father.

Five years ago, father's age was 4 times his son's age.

To Find:

What are their present ages?

Process:

To find their present ages we will first let the father's age be x. Then, son's age will be x/3. Five years ago son's age will be (x/3 - 5) and father's age will be (x - 5). It is given father's age was 4 times son's age. So, we can form an equation as follows:

x - 5 = 4(x/3 - 5)

After solving the equation to get the value of x, the value of x is equal to the age of the father and x/3 will be the age of the son.

Solution:

Let the father's age be x.

Then, the son's age will be x/3.

Five years ago:

Son's age = (x/3 - 5)

Father's age = (x - 5)

∵ Five years ago father's age was 4 times his son's age. [given]

x-5=4(x/3-5)

x-5=4x/3-20

x-4x/3=5-20

3x-4x/3= -15

-x/3= -15

-x= -15×3

-x= -45

x=45

Hence, value of x is 45.

Therefore, father's age = x = 45 years

And son's age = x/3 = 45/3 = 15 years

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