Question

1. The sum of 4 times a larger integer and 5 times a smaller integer is 7. When
twice the smaller integer is subtracted from 3 times the larger, the result is 11.
Find the integers.​

Answer 1

Answer:

Here is your answer.

Step-by-step explanation:

4x+5y=7

3x−2y=11

8x+10y=14

15x−10y=55

23x=69

x=3

4(3)+5y=7

12+5y=7

5y=−5

y=−1

x=3 , y=−1.

Hope it helps u. If it helps mark the answer as brainliest.