Question

1. The sum of 4 times a number and 3 times its reciprocal is 7 find the no.

2. 2YRS AGO MY AGE WAS 41/2 TIMES THE AGE OF MY SON 6YRS AGO MY AGE WAS TWICE THE SQUARE OF THE AGE OF SON WHAT IS THE PRESENT AGE OF SON

3. IN A TWO DIGIT NO. THE DIGIT IN THE UNITS PLACE IS EQUAL TO THE SQUARE OF THE DIGIT AT TENSE PLACE IF 54 IS ADDED TO THE NO THE DIGIT GET INTERCHANGED FIND THE NO.

I WILL MARK U AS THE BRAINLIEST AND 25 POINTS BONUS

Answer 1

Step-by-step explanation:

• Let the number be X . Then it's reciprocal will be 1/X. Hence, The number will be 1 OR 3/4.
• Let the son's age two years ago be x. According to question, his age was twice the square of his son's age. Two years ago, his son's age is 4 years. So, the present age of his son is 4+2=6 years.
• In a two digit no. the digit at unit place is equal the square of the digits at tens place. y 54 is added to the no. the digits get interchanges.