Question

1) The sum of a two digit number and the number obtained by reversing the digits
is 165. The digit at tens place is 1 more than the digit at unit place. Find the
number.
explain step by step...​

Answer 1

Step-by-step explanation:

Let the unit digit be x

then the tens digit will be x+1

The original number:

10(tens digit)+unit digit

=10(x+1)+x

=10x+10+x

=11×+10

The reversed number

=10x+x+1

=11x+1

According to the question

(11x+10) +(11x+1) = 165

22x+11=165

22x=165-11

22x=154

x=7

The original number=11x+10

=77+10

=87

Answer 2

Answer:

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Step-by-step explanation:

let the required two digit number be 10x+y

wherein digit at tens place is x and that of units place is y

so thus number obtained by reversing digits is

10y+x

so according to first condition

10x+y+10y+x=165

ie 11x+11y=165

so x+y=15 (1)

according to the second condition

x=y+1 (2)

substitute value of x in (1)

we get

2y=14

ie y=7

so substitute value of y in any of two equations

we get

x=8

so our required two digit number=10x+y

=(10×8)+7

=80+7

=87

hence our required two digit number is i7