1. The sum of a two number is 12. If the new no
formed by seversing the digits is greater than the
original no. by 18. Finde the original no.
Answers
Answer:
Step-by-step explanation:
Let the two digits be x and y
Given that: sum of x and y is 12
= x + y = 12
Therefore the original number = 10x+y
(For example) As if a no. is 21 then 10×20+1
Is the same no. Written in another way.
Therefore the reversed no = 10y + x
Given that: reversed no. - original no. = 18
= (10y+x) - (10x+y) = 18
= 10y+x -10x -y = 18
= 9y-9x = 18
By dividing with 9 on both sides
= y-x = 2
Then y = x + 2
Using this equation in the first equation
x + y = 12
On putting value of your
= x + (x+2) = 12
= 2x + 2 = 12
= 2x =12-2
= 2x = 10
x = 10 ÷ 2
x = 5
By putting value of x in equation x+ y= 12
5 +y = 12
y = 12 - 5
Then,y = 7
Original no. = 10x+y
= 10 × 5 + 7
= 50 + 7
= 57