Question

1. The sum of digits of a two digit number is 7. If 5 times of tens digit is 2 less than half of the number, find the number.
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Answer 1

Answer:

let the no. at tens place to be X and that at ones place to be y.

Therefore, 2 digit no.=10x+y

Step-by-step explanation:

x+y=7.........(i)

50x=(10x-y)-2

50x=10x-y-2

50x-10x+y=-2

40x+y=-2.........(ii)

Subtracting equation (i) from (ii)

40x+y=-2

- x+y=7

-. -. -

__________

39x