1. The sum of five consecutive integers is zero. Find the product of these integers.
2. The numerator of a fraction is 3 less than its denominator. When both the
numerator and the denominator are increased by 1 the fraction become 2/3.find the fraction.
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I) Product of the integers=0
2,) fraction is 1/2
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- denominator= x
- numerator= 3+x
- x+1/3+x+1=2/3
- x+1/3x+4=2/3
- 3(x+1) = 2(3x+4)
- 3x+3=6x+8
- 3x-6x=8-3
- -2x=5
- x=5/2
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