Question

1. The sum of four consecutive odd numbers is 80. Find the numbers.​

Answer 1

Let the consecutive odd numbers=x, x+2,x+4, and x+6 respectively.

So,

x+(x+2)+(x+4)+(x+6)=80

4x+(2+4+6)=80

4x+12=80

(4x÷4)+(12÷4)-(12÷4)=(80÷4)-(12÷4)

x+3–3=20–3

x+0=17

x=

17

Given that x=17, then x+2,x+4,and x+6=

19,21, and 23 respectively.

Proof:

17+19+21+23=80

This identity establishes the 4 consecutive odd numbers that = 80

Answer 2

Answer:

17,19,21,23

Step-by-step explanation:

x+x+2+x+4+x+6=80

4x+12=80

4x=80-12

x=68/4

4 no.s are 17 ,19,21,23

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