Question

1 The sum of the 4th and 8th terms of an AP is 24 and the sum of the 6th and 10th terms is 44 find first three terms of AP​

Answer 1

Answer:

T4 = a+3d

T8 =a+7d

Therefore,

a+3d+a+7d=24

2a+10d=24

a+5d=12 …… (1)

Again,

T6=a+5d

T10 =a+9d

Therefore,

a+5d+a+9d=44

2a+14d=44

a+7d=22 ……. (2)

Solving equations (1) and (2), we get

d=5 and a=−13

First term = a = -13

second term = a+d = 5+(-13) = -8

third term = a+2d = -13+2(5) = -3

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