Question

1) The sum of the ages of two friends is 20 yrs.Taking the present age of first friend as x yrs, find the present age of the second. Also find their ages 2 yrs ago in terms of x. If the product of their ages 2 yrs ago is 60 yrs. Find their present ages.

Plz write in full method​

Answer 1

Answer:

12 , 8 is the required answer

Step-by-step explanation:

Given:

1. The sum of the ages of two friends is 20 years:

2. if present age of one of the friend is x yrs then, 20-x

According to question:

 (x-2)(20-x-2) = 60

or, (x-2)(18-x) = 60

or, x(18-x)-2(18-x) = 60

or, $18x - x^{2} -36+2x = 60$

or, $-x^{2} +20x-96 = 0$

or, $x^{2} -12x-8x-96 = 0$

or, $x(x-12)-8(x-12) = 0$

or, $(x-8)(x-12) = 0$

or, x = 8,12

Hence, The present ages of both friends will be 12 and 8 respectively: