Question

1. The sum of the digits of a two-digit number is 15. If the number formed by reversing the digits 15
less than the original number by 27, find the original number.
2.
The sum of the digits of a two-digit number is 12. If the number formed by reversing the digits is
greater than the original number by 54, find the original number.
3. The digit in the tens place of a two-digit number is three times that in the units. If the digits are​

Answer 1

1.

Let the unit's place=x

Then the ten's place=15−x

∴ original number=10(15−x)+x=150−10x+x=150−9x

By reversing the digits, we get

New number=10x+(15−x)=10x+15−x=9x−15

According to the problem,

original number−New number=27

⇒150−9x−9x+15=27

⇒−18x+165=27

⇒−18x=27−165=−108

⇒x=

−18

−108

=6

Hence original number=150−9x=150−9×6=150−54=96

2.

i have given the pic above

3.

ANSWER

Let the one's digit be y and tens digit be x,

Number = 10x + y

Then,x=3y⋯(i)

Reversed number = 10y + x

A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)

⇒9x−9y=36

⇒x−y=4⋯(ii)

⇒3y−y=4

∴2y=4 x=3y ∴x=6

y=2

∴ Number = 62

hope it helps you.....

Answer 2

Answer:

2.39

Step-by-step explanation:

3.can be these 93,62,31,

1.96