Question

1.

The sum of the digits of a two-digit number is 7. The number obtained by interchanging the digits exceeds
the original number by 27. Find the number.

2.

The tens place digit of two-digit number is twice the digit of unit place digit. The number obtained by
interchanging the digits diminished the original number by 36. Find the number.​

Answer 1

HEY MATE

HERE'S YOUR ANSWER

ANSWER NO. 1.

TENS PLACE ONES PLACE

X 7-X

THEN,THE NO. IS 10X+7-X=9X+7

REVERSING THE DIGITS

X+10(7-X)=X+70-10X=70-9X

ACCORDING TO GIVEN STATEMENT

=→ 70-9X=(9X+7)+27

=→ 70-9X=9X+7+27

=→ -9X-9X=34-70

=→ -18X=-36

=→ 18X=36

=→ X=2

TENS PLACE=2

ONES PLACE=7-X=7-2=5

THE NUMBER IS 25.

THANKS

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