Question

1. The sum of the squares of 3 consecutive
positive numbers is 365. Accordingly,
what is the sum of those numbers ?​

Answer 1

Answer:

Step-by-step explanation:

Let the 3 consecutive positive numbers = x, x +1, x + 2

According to the question,

=> x2+(x+1)2+(x+2)2=365

=> x2+x2+1+2x+x2+4+4x=365

=> 3x2+6x−360=0

=> x2+2x−12=0

=> x×(x+2)=120

=> x(x+2)=10×12=120

=> x = 10

Therefore, Sum of the numbers = 10 + 11 + 12 = 33