1. The sum of three consecutive numbers is 24. Find the numbers,
2. How many times 15 may be subtracted from the difference of the largest
and the smallest numbers formed with the digits: 5, 0, 3 and 0?
12
7.
1
Answers
Answer:
1)To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 24
3X + 3 = 24
3X + 3 - 3 = 24 - 3
3X = 21
3X/3 = 21/3
X = 7
Which means that the first number is 7, the second number is 7 + 1 and the third number is 7 + 2. Therefore, three consecutive integers that add up to 24 are 7, 8, and 9.
7 + 8 + 9 = 24
We know our answer is correct because 7 + 8 + 9 equals 24 as displayed above.
Step-by-step explanation:
2)Given numbers are 8,0,2,7,5 and 9.
If given digits are allowed to repeat any digit then, the largest number (9).
Then largest number is 9,99,999.
Smallest number is 2,00,000 and difference is 7,99,999.
If repeating is not allowed then largest number is 9,87,520 and smallest number is 2,05,789.
Then difference of numbers is 7,81,731.
Answer:
1. 7,8,9 2. 351
Step-by-step explanation:
1. Let the no.s be x, x+1 and x+2
So, x + x+1 +x+2 = 24
=> 3x + 3 = 24
x + 1 = 8
x = 7
So, the numbers are 7,8,9.
2. Largest number formed = 5300, Smallest no. formed = 0035 = 35
So, difference = 5265
Therefore, no. of times 15 can be subtracted = 5265/15 = 351