Question

1. The sum of three numbers is 58. The second number is three times of two fifth of the first
number and the third number is 6 less than the
in first number. find the three numbers ​

Answer 1

Answer:

The required 3 numbers are 20, 24 and 14

Step-by-step explanation:

Let the 3 numbers be x,y and z

As per given data,

$x+y+z=58$........(1)

$y=3(\frac{2x}{5})$

$y=\frac{6x}{5}$......(2)

$z=x-6$........(3)

using (3) in (1), we get

$x+y+(x-6)=58$

$2x+y=64$

Using (2) in this equation, we get

$2x+\frac{6x}{5}=64$

$\implies\frac{10x+6x}{5}=64$

$\implies\,16x=320$

$\implies\,x=\frac{320}{16}$

$\implies\boxed{\bf\,x=20}$

put x=20 in (3), we get

$z=20-6=14$

$\implies\boxed{\bf\,z=14}$

put x=20 in (2), we get

$y=\frac{6(20)}{5}$

$y=6(4)$

$\implies\boxed{\bf\,y=24}$

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Answer 2

Answer:

x = 20 , y = 24 , z = 14

Step-by-step explanation:

Let the 3 numbers be x , y , z

x = x , y = 3(2x/5) , z = x-6

The sum of the 3 numbers is 58

x + y + z = 58

x + 6x/5 + (x - 6) = 58

2x + 6x/5 = 64

16x/5 = 64

16x = 320

so, x = 20

y = 6x/5 = 24

z = (x - 6) = 14