Question

(1) The sum of two numbers is 35. If one number is 6 times the other, then the smaller is ?
(a) 5
(b) 6
(c)7
(d) 8​

Answer 1

Answer:

Step-by-step explanation:

To attempt this question, we need to make the following assumptions:-

Let the first number be x.

Let the second number be y.

Now, we can write the equations according to the question:-

x + y = 35 ----------------------- [1]

Let x = 6y

We can conclude that x > y.

Substitute the following in equation [1],

We get:-

6y + y = 35

7y = 35

y = $\dfrac{35}{7}$

y = 5 is the answer.

Next, we need to find x.

x = 6y

x = 6(5)

x = 30 is the answer.

So, the two numbers are 30 and 5.

Verification:-

Since we have the sum as x and y,

30 + 5 = 35 [LHS]

35 {RHS}

So, LHS = RHS.

Hence, Proved!

Answer 2

Given that , The sum of two numbers is 35 , & one number is 6 times the other .

Exigency To Find : The smaller number ?

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

❍ Let's Consider the smaller number ( or first number ) be x .

⠀⠀⠀⠀⠀Given that ,

⠀⠀⠀⠀➠⠀The other number ( or Second number ) is 6 times the other .

Therefore,

• The other number ( or Second number ) is 6x .

⠀⠀⠀⠀⠀⠀$\underline{ \pink {\boldsymbol{\star\:According \: to \: the \: Question \::}}}$

⠀⠀━━━ The sum of two numbers is 35 .

$\qquad \dashrightarrow \sf First \:Number \:\:+ \:\: Second \:number \:\:=\:\: 35 \:$

$\qquad \dashrightarrow \sf x \:\:+ \:\: 6x \:\:=\:\: 35 \:$

$\qquad \dashrightarrow \sf \:\:7x \:\:=\:\: 35 \:$

$\qquad \dashrightarrow \sf \:\:x \:\:=\:\: \dfrac{35}{7} \:$

$\qquad \dashrightarrow \sf \:\:x \:\:=\:\: \cancel {\dfrac{35}{7}} \:$

$\qquad \dashrightarrow \sf \:\:x \:\:=\:\: 5 \:$

$\qquad \dashrightarrow \:\:\pmb{\underline{\purple{\frak{\:\:\:x \:= \:5 }}} }\:\:\bigstar$

Therefore,

• The smaller number ( or first number ) is x = 5 , &
• The other number ( or Second number ) is 6x = 6(5) = 30 .

$\qquad \therefore \:\:\underline {\sf \:Hence, \:The \:smaller \:number\:is \:\pmb{\bf{ 5 }}\:\:}.$