1. The sum of two numbers is 4980. If 13% of the one number is equal to 17% of the other. Find thenumber.
Answers
Answer:
The required numbers are 2822 & 2158.
Step-by-step-explanation:
Let the first number be x.
And the second number be y.
From the first condition,
x + y = 4980 - - ( 1 )
From the second condition,
13% of x = 17% of y
⇒ 13% * x = 17% * y
⇒ 13 / 100 * x = 17 / 100 * y
⇒ 13 * x / 100 = 17 * y / 100
⇒ 13x / 100 = 17y / 100
⇒ 13x = 17y - - [ Multiplying both sides by 100 ]
⇒ x = 17y / 13 - - ( 2 )
Now,
x + y = 4980 - - ( 1 )
⇒ ( 17y / 13 ) + y = 4980 - - [ From ( 2 ) ]
⇒ 17y / 13 + y = 4980
⇒ ( 17y + 13y ) / 13 = 4980
⇒ 17y + 13y = 4980 × 13
⇒ 30y = 64740
⇒ y = 64740 ÷ 30
⇒ y = 2158
By substituting y = 2158 in equation ( 2 ), we get,
x = 17y / 13 - - ( 2 )
⇒ x = 17 × 2158 / 13
⇒ x = 17 × ( 2158 ÷ 13 )
⇒ x = 17 × 166
⇒ x = 2822
∴ The required numbers are 2822 & 2158.