Question

1. The sum of two numbers is 4980. If 13% of the one number is equal to 17% of the other. Find thenumber.​

Answer 1

Answer:

The required numbers are 2822 & 2158.

Step-by-step-explanation:

Let the first number be x.

And the second number be y.

From the first condition,

x + y = 4980 - - ( 1 )

From the second condition,

13% of x = 17% of y

⇒ 13% * x = 17% * y

⇒ 13 / 100 * x = 17 / 100 * y

⇒ 13 * x / 100 = 17 * y / 100

⇒ 13x / 100 = 17y / 100

⇒ 13x = 17y - - [ Multiplying both sides by 100 ]

⇒ x = 17y / 13 - - ( 2 )

Now,

x + y = 4980 - - ( 1 )

⇒ ( 17y / 13 ) + y = 4980 - - [ From ( 2 ) ]

⇒ 17y / 13 + y = 4980

⇒ ( 17y + 13y ) / 13 = 4980

⇒ 17y + 13y = 4980 × 13

⇒ 30y = 64740

⇒ y = 64740 ÷ 30

⇒ y = 2158

By substituting y = 2158 in equation ( 2 ), we get,

x = 17y / 13 - - ( 2 )

⇒ x = 17 × 2158 / 13

⇒ x = 17 × ( 2158 ÷ 13 )

⇒ x = 17 × 166

⇒ x = 2822

∴ The required numbers are 2822 & 2158.