1)The surface area of a solid metallic sphere is 616 cm2. It is melted and recast into smaller
spheres of diameter 3.5 cm. How many such spheres can be obtained?
2)The surface area of a solid metallic sphere is 1256 cm2. It is melted and recast into solid
right circular cones of radius 2.5 cm and height 8 cm. Calculate:
(i) the radius of the solid sphere.
(ii) the number of cones recast. (Use π= 3.14).
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Answer:Hope this is help full
Step-by-step explanation:
Solution:-
Surface area of the sphere = 4πr²
616 = 4*22/7*r²
r² = (616*7)/88
r² = 4312/88
r² = 49
r = 7 cm
Radius of the sphere is 7 cm
As sphere is melted and recast into a cone then,
Volume of the sphere = Volume of the cone
4/3πr³ = 1/3πr²h
4/3*22/7*7*7 = 1/3*22/7*r²*28
4/3*7*7*7 = 1/3*r²*28
r² = 49
r = 7 cm
So, radius of the cone is 7 cm and diameter = 7*2 = 14 cm
Answer.
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