Question

1..
the the sum of two integers is minus 16 if one of them is 53 find the other..
2..
the sum of two integers is 65 one of them is - 31 find the other..
3..
if a is equal to minus 8 b is equal to minus 7 C is equal to 65 that (a + b) + C is equal to a + (b +) .​

Answer 1

Step-by-step explanation:

1. x+53 = -16

x = -89

2. -31+x = 65

x = 96

Answer 2

Step-by-step explanation:

GIVEN THAT:-

(1) The sum of two integers is -16 in which one of them is 53....

LET :- The second integer number is "X"

SOLUTION:-

$x + 53 = - 16 \\ = > x = - 16 - 53 \\ = > x = - 69$

Hence the second number is -69

(2) the sum of two integers is 65 one of them is - 31

LET :- second number is "X"

SOLUTION:-

$x + ( - 31) = 65 \\ = > x = 65 + 31 \\ = > x = 96$

Hence the second integer number is 96

(3)

GIVEN THAT:-

$a = - 8 \\ b = - 7 \\ c = 65$

proof that :-

$(a + b) + c = a + (b + c)$

SOLUTION:-

$LHS = (a + b) + c = ( - 8 - 7) + 65 \\ = - 15 + 65 = 50 \\ \\ \\ now \\ RHS = a + (b + c) = - 8 + ( - 7 + 65) = - 8 + (58) = 50$

hence proved