1.the two sides of a parallelogram are int he ratrio 5 isto 4. if its perimeter is 54 cm . find the lenght of the largest side
2.the three angles of a quadreilatera are 76 degree,54degree and 130 fegree.fin the fouth angle
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(1.) perimeter of parallelogram=2(l+b)
54=2(l+b)
let the common multiple be x
as the ratio of the two sides is 5:4
then
54=2(5x+4x)
54=2×9x
54=18x
x=3
the length (largest side)=5x
=5×3
=15cm
(2.)sum of all the four angles in a quadrilateral is always 360°
so
76+54+130+x=360
260+x=360
x=360-260
x=100°
hope it helps.....
steveshaju25:
could you answer this also please
ok
2 questions are there
1.if the ratio of two adjacent angles of a parralelogram is 2isto 3. fin all the angles of a parralaelogram
2.the perimeter of a parralelofeam is 150 cm . one of the sides is greater than the other by 25cm . find the length of all ide of paraleleogram.
2:3. take x as a common factor, so (2x + 3x)*2= 360, 5x =180, x = 36, 72 and 108
let a and b are adjacent sides of a llgram, then (a+b)*2= 150, a+b=75, now as given a = 25+b put the value of a in the equation, we get, 25+b+b=75, 2b=50, b = 25 hence a = 50, so sides are 25,25,50.50
(1.) ratio of two adjacent angles in a quadrilateral is 2:3. In parallelogram adjacent angles are supplementary angles. Let the common multiple be x. As the ratio of the two angles is 2:3 so ; 2x+3x=180 ; 5x=180 ; x=36°
so the angles of the parallelogram measures 2x=2×36=72 ; 3x=3×36=108
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