Question

1)The value of 0.23 bar +0.22 is______.

2)In the figure if AOC=50 degree then (ANGLE AOD +ANGLE COB)is equal to:​

Answer 1

1)The value of 0.23 bar +0.22 is 0.45bar.

2)In the figure if AOC=50 degree then (ANGLE AOD +ANGLE COB)is equal to:

given:

angle AOC = 50

since AOC and DOB are opposite Angle.... AOC = DOB

total angel here = 360

AOD + COB +AOC+ DOB = 360

AOD + COB +50+50=360

AOD + COB = 360 -100

therefore

AOD + COB = 260

Answer 2

Answer:

okkk dear it's my pleasure to chat with uu! wat doubtss ask!!

note:don't forget to the brainliest!!!!!

ok it's late dear good nyt!!