Physics, asked by hemangidamor48, 3 months ago


(1) The value of 1 division on main scale of a vernier calipers (MSD) =________ cm
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Answers

Answered by samyuta
0

Explanation:

Solution: From the given data, one main scale division (MSD) and one Vernier scale division (VSD) are 1 MSD = 5.15 - 5.10 = 0.05 cm and 1 VSD = 2.45/50 = 0.049 mm. The least count of the given Vernier Calipers is LC = 1 MSD - 1 VSD = 0.001 cm.

Answered by kishanmkish89
0

Explanation:

1 MSD = 5.15 - 5.10 = 0.05 cm and 1 VSD = 2.45/50 = 0.049 mm.

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