Question

= = 1. The value of k for which the system of equations kx - y = 2 and, 6x - 2y = 3 has a unique solution, is (a) =3 (6) = 3 (c) ²0 13. (d) = 0​

Answer 1

kx-y=2

6x-2y=3

For a unique solutions

a1/a2 ≠ b1/b2

k/6≠-1/-2

k= 3

a) 3 ✔

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Answer 2

Answer:

ans= k= 3

Step-by-step explanation:

kx-y=2. (i)

6x-2y=3. (ii)

equation have unique solution =a1 /a2 not equal to b1 / b2

k/6=-1/-2= 2k = 6

k= 6/2= 3

k=3