Math, asked by piyush445635, 8 months ago

1. The value of q in the equation 29 + 6 = 12 is
2. The value of t in 16 = 4 + 3 (1 + 2) is
19
3. 7m +
= 13, where m =
2.
4. If 3x - 2(2x - 5) = 2(x + 3) - 8, then x is equal to
5. If
y-1 y - 2
= 1, then the value of y is
3
6.
is the fraction when four is added to
26
twice a number yielding
5
7. Two consecutive positive odd integers whose
sum is 76 are
8. In a class of 49 students, the number of girls
1
is times the number of boys. The number of
6
boys are and the number of girls are
in the class.
9. Hari is twice as old as his son. Twenty years
ago, he was four times as old as his son.
The present age of Hari is
years
10. Five times a number increased by two gives 32
The number​

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Answers

Answered by Anonymous
3

Answer:

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Step-by-step explanation:

1) 2q+6=12

2q=12-6

2q=6

q=6/2

q=3.

2) Given simple equation :

16=4+3(t+2)

=> 16=4+3t+6

=> 16=10+3t

Subtract 10, both sides of the equation ,we get

=> 16-10=10-10+3t

=> 6 = 3t

Divide each term by 3 , we get

=> 2=t

3) 7m+19/2=13

14m+19/2=13

14m+19=26

14m=26-19

14m=7

m=7/14

m=1/2

4) 3x-4x+10 = 2x + 6- 8

-x+10 = 2x -2

-x-2x = -2-10

-3x = -12

x =12/3

x = 4

5) y-1/3 - y - 2/4 = 1

Take the LCM,

4(y-1)-3(y - 2)/12 = 1

4y-4-3y+6=12

y+2=12

y=12-2

y=10

6) let the number be x

A.T.Q.

4+2x=26/5

2x=26/5-4

2x= 26/5-20/5

2x = (26-20)/5

2x = 6/5

x = 6/5×1/2

x = 3/5

7) Let the two consecutive positive odd integers be n and n+2, where n is an odd positive integer.

Then, according to the given information, we have

sum of n and n+2 = 76

n+n+2=76

2n=74

n=74/2

n=37

Therefore, the odd positive integers are

n, n+2 = 37, 37+2 = 37, 39.

8)Given

Total =49

Girls =1/6 of boys

Let the boys =x

Then girls=x/6

total = x+x/6

x+x/6=49

6x+x/6 = 49

7x=49*6

x=7x6=42

x=boys=42

Girls=49-42=7

9) Let the present age of Hari be x yrs

And present age of son be y yrs

ATQ,

x = 2y --------------------(i)

20 yrs ago,

Hari's age = (x-20) yrs

Son's age = (y-20) yrs

=> (x-20) = 4(y-20)

=> x-20 = 4y-80

Putting the value of x

2y-20 = 4y-80

=> 2y-4y = -80+20

=> -2y = -60

=> 2y = 60

=> y = 30

x = 2y

= 2×30

= 60

10) Let the number be x

Five times a number = 5 × x = 5x

Five times a number increased by 2 = 5x + 2

Their result is 32

According to the question,

5x + 2 =32

➾ 5x = 32 - 2

➾ 5x = 30

➾ x =30/5

➾ x = 6

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