Question

1. The value of
$\sqrt{6 + \sqrt{6 + \sqrt{6 + ..........} } }$
is......
(a) 4 (b) 3 (c)-2 (d)7/2​

Answer 1

Step-by-step explanation:

Heya.....refer to the attachment

Answer 2

Answer:

The answer is (b) 3.

Step-by-step explanation:

Let, √6+√6+√6+... be x

=> x = √6+√6+√6+...

Squaring both the sides.

=> x² = 6+√6+√6+...

Now putting that x = √6+√6+√6+...

=> x² = 6+x

=> x²-x-6 = 0

=> (x-3)(x+2) = 0

=> x = 3, -2

The sum to infinity can't be negative. So, that x=3.