Question

1
The value of * V5.76 is-
V0-09
(A) 0.8
(B) 0.08
(C) 8
(D) 6.4​

Answer 1

Let the current in OA , OB and OC be I

1

, I

2

and I

3

respectively and direction of all the three currents

be towards O.

Applying Kirchoff's law at O :

I

1

+ I

2

+ I

3

= 0

10

V

0

−10

+

20

V

0

−6

+

30

V

0

−5

= 0

60

6(V

0

−10)+3(V

0

−6)+2(V

0

−5)

= 0

V

0

= 8