Question

1. The wave is moving with the speed 3000 cm / s with reversal after each 0.01 sec. Determine the wavelength of the wave.​

Answer 1

Answer:

The wavelength of wave is 30 cm

Explanation:

Given as :

The speed of wave = v = 3000 cm/s

The time period of each reversal = t = 0.01 sec

Let The wavelength of wave = $\lambda$ cm

∵ The wavelength of wave = $\dfrac{velocity}{frequency}$

Let The frequency = f

Since Frequency = $\dfrac{1}{t}$

Or, f = $\dfrac{1}{0.01}$

i.e f = 100 per sec

Now,

The wavelength of wave = $\dfrac{3000}{100}$

Or, $\lambda$  = 30 cm

So, The wavelength of wave =  $\lambda$  = 30 cm

Hence, The wavelength of wave is 30 cm Answer

Answer 2

Answer:

The wavelength of wave is 30 cm

Explanation:

Given as :

The speed of wave = v = 3000 cm/s

The time period of each reversal = t = 0.01 sec

Let The wavelength of wave =  cm

∵ The wavelength of wave =  

Let The frequency = f

Since Frequency =  

Or, f =  

i.e f = 100 per sec

Now,

The wavelength of wave =  

Or,   = 30 cm

So, The wavelength of wave =    = 30 cm

Hence, The wavelength of wave is 30 cm Answer