Chemistry, asked by calebnduaesa, 3 months ago

1. The wavelength of a violet light is 400 nm. Calculate the frequency and wavenumber.

Answers

Answered by mantu9000
12

Given:

The wavelength of a violet light (\lambda) = 400 nm = 400 × 10^{-9} m

We have to calculate the frequency(\nu\nue) and wave number.

Solution:

∴ Frequency(\nu\nue) = \dfrac{c}{\lambda}

Where, c = velocity of light = 3 × 10^{8} m

Frequency(\nu\nue) = \dfrac{3\times 10^{8} }{400\times 10^{-9} }

= \dfrac{3\times 10^{8} }{400\times 10^{-9} }

= 0.0075 × 10^{17} Hz

= 7.5 × 10^{14} Hz

Also,

Wave number = \dfrac{1}{\lambda}

= \dfrac{1}{400\times 10^{-9} }

= 0.0025 × 10^{9} m^{-1}

= 2.5 × 10^{6} m^{-1}

∴ Frequency(\nu\nue) = 7.5 × 10^{14} Hz and

Wave number = 2.5 × 10^{6} m^{-1}

Answered by dualadmire
17

Given:

The wavelength of the violet light = 400nm

To find:

The frequency and the wave number of the violet light used.

Solution:

The frequency is given as: f = c/λ

Where c is the speed of light in vacuum. Therefore:

f = 3*10⁸ / 400*10⁻⁹ = 7.5*10¹⁴ Hz

Wave number is given as: w= 1/λ

w = 1/ 400*10⁻⁹ = 2.5*10⁶ m⁻¹

Therefore the frequency of the violet light is 7.5*10¹⁴ Hz and its wave number is 2.5*10⁶ m⁻¹.

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