1. The wavelength of light of a particular colour is 5800 angstrom. Express it in a) nanometer and b) meter
Class 9 ICSE
Ch - Measurements and Experimentation.
Answers
Answered by
31
Hey there!
It's easy!
5800 5800 Angstroms = 580 nano meter
--------------------------------------------------------
5800 Angstroms = 5.8 × 10⁻⁷ meter
Hope It Helps You!
✧══════•❁❀❁•══════✧
.
It's easy!
5800 5800 Angstroms = 580 nano meter
--------------------------------------------------------
5800 Angstroms = 5.8 × 10⁻⁷ meter
Hope It Helps You!
✧══════•❁❀❁•══════✧
.
Answered by
41
Hey there!
a) 5800 angstrom into manometer
1 angstrom = 10^-1 nm
5800 angstrom = 5800/10 nm = 580 nm
b) 1 angstrom = 10^-10 m
5800 angstrom = 5800/ 10^10 = 5.8 * 10^-7 m
Hope It helps You!
Similar questions