Question

1) The weight of stone in air is 180N and it's weight in water is 90N
Calculate the buoyancy experienced by the stone?
2)Ink can be blotted with chalk why?
3)Why the body of person who get electric massaged well?
4)Write down the factors effecting buoyancy?
5)The area of one end of a U-tube is 1 m² and that of other end is 10 m²
When a force was applied on the liquid at the first end the force experienced at the other end was 200N,what was the force applied on the liquid at the first end?

Answer 1

HOPE IT HELPS.!!!!!!!!.

Explanation:

1) Given that,

Weight of body in air = 100 N

Buoyant force = Weight of liquid displaced

Volume of water displaced = 400 cc

2

Density of water = 1g/cm3

In this case,

ρ=

V

m

m=ρ×V

m=1×400

m=400g

We know that,

The weight of water displaced is

W=m×g

W=

5

2

×9.8

W=3.92N

Now, weight of the object in water

W=100−3.92

W=96.08

W=96N

Hence, the weight of object in water is 96 N