Question

(1) The zeroes of polynomial p (x)= x(x+2)(x-3) are
(a) 2,-3 (b) 0 (c)-2,3 (d) 0,-2,3

Answer 1

Answer:

C is the correct answer

Step-by-step explanation:

Let put the value to check:

X= -2

x(x+2)(x-3)

-2(-2+2)(-2-3)

4 -4 × - 5

0×-5=0

x=3

3(3-2)(3-3)

9-6×0

3×0 = 0

So our assumption is right