Question

(1) The zeroes of the polynomial 6y2 - 11y – 7 are (a)1/2, 7/3 (b) -1/3, 7/ 2 (c) -1/2, 7/3 (d) 1/3, -7/2

(2) The zeroes of the polynomial 4x2 - 4x +1 are (a) ¼, ¼ (b) ½, ½ (c) -1/4, -1/4 (d) -½, -1/2

(3) If-3 is one of the zeroes of the quadratic polynomial (k-1) x² + kx-3, then the value of k is (a) -1/2 (b) 1/2 (c)-2 (d) 2 17

(4) What constant should be added to the polynomial x² + 7x + 5 so that -2 is a zero of the resulting polynomial? (a) -4 (b) -5 (c) 5 (d) 4

(5) The zeroes of the quadratic polynomial x2 +99x + 127 are (a) both positive (c) one positive and one negative (b) both negative (d) both equal​

Answer 1

Answer:

Use this Example and try to slove if not please inform me so that I can give you the brief about it My Name {Geetha}

Step-by-step explanation:

(i)  2a + b + 7 ; 4a + 2b + 3

    2a +   b + 7

    4a + 2b + 3    

   -------------------

   6a + 3b + 10

Answer 2

Calculate

$\huge{ \orange{ \displaystyle \lim_{n \to \infty} \frac{1}{n} \biggl \{ \displaystyle{} (m + 1) (m + 2). \: . \: . \: .(m + n) \biggl \} {}^{ \frac{1}{n} } }}$