Question

1. There are 104 students in class 10 and 96 students in class 9 in a school. In
a house examination the students are to be evenly seated in parallel rows
such that no two adjacent rows are of same class. Find
(i) The maximum number of parallel rows of each class for seating
arrangement.
(ii) The number of students of class 9 and also of class 10 in a row.​

Answer 1

Answer:

There are a total of 200 students (104 and 96).

Both 104 and 96 are divisible by 8, i.e. 104/8 = 13 and 96/8 = 12.

a). Therefore the maximum number of parallel rows would be 12+13 = 25. And, 200/8 = 25.

b). Number of students in each row would be 8.