Question

1. There are 18 tickets marked with numbers 1 to 18. What‘s the probability of selecting a ticket having the following property:
a) even number   
b) number divisible by 3
c) prime number   
d) number divisible by 6

Answer 1

Step-by-step explanation:

s = { 1 ,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18}

n (s)= 18

A = { 2,4,6,8,10,12,14 ,16,18 }

n ( A) = 9

P(A) = n(A)/n(s)

9/18 = 1/2

B = { 3,6,9,12,15,18 }

n(B)= 6

P(B) = n(B)/n(s)

6/18 = 1/3

C = { 2,3,5,7,11,13,17}

n(C)= 7

P(C) = n(C)/n(s)

7/18

D = { 6,12,18}

n(D) = 3

P(D) = n(D) / n(s)

3 /18 = 1/6