Question

1. There are five brothers in a family average salary of 4 elders brothers is Rs. 740.
Now the youngest brother starts earning and the average salary of all brothers
decreases by Rs. 34. If the eldest brother takes a leave and starts another work
then his monthly salary is Rs. 80 more than the youngest brother Now the average
salary is reduced to Rs. 636. Find the initial salary of eldest brother and youngest
brother.​

Answer 1

Answer:

Initial salary of eldest brother=Rs. 1000

and Yongest brother= Rs. 570

Step-by-step explanation:

At first Total salary of 4 elders person= (740*4)=Rs.2960

when Yongest brother starts earning total salary of 5 brothers = (740-34)*5 = Rs. 3530

Salary of Yongest brother= (3530-2960)

= Rs. 570

Now New salary of the eldest brother= (570+80)

= Rs. 650

Now total salary of them = (636*5)= Rs. 3180

Difference in total salary= 3530-3180= Rs.350

Initial salary of eldest brother= (650+350)

= Rs.1000

Answer 2

Solutions:-

The average salary per months of the eldest four = ₹740

Total Salary per month of the eldest four = 4 × 740 = ₹2960

Average salary per month of the five = 740 - 34 = ₹706

Total Salary per month of the five = 5 × 706 = ₹3530

Therefore, salary of the youngest = 3530 - 2960 = ₹570

And the salary of the eldest leave = 570 + 80 = ₹650

Average salary of the five after the leave of the eldest = ₹636

Total Salary of the five after the leave of the eldest = 5 × 636 = ₹3180

Total Salary of the middle three = 3180 - 570 - 650 = ₹1960

Therefore, the salary of the eldest before leave = 2960 - 1960 = ₹1000.