Question

1. There are two parks A and B as shown. Ajay
walks around park A and Vijay walks around
park B.
30 m
Park A
30 m
Park B
75 m
75 m
a) Who walks more distance?
b) Which park has greater area?​

Answer 1

If park A is 30m x 30 m and park B is 75m x 75m then Vijay walks more distance and Park B is greater with an area of 5625 m².

Step-by-step explanation:

Case (a): Who walks more distance?

Since we are given that both Ajay and Vijay walks around park A and Park B respectively, therefore here we have to find the perimeter of each of the parks to find the who has covered more distance.

For Park A:

Length = 30 m

Breadth = 30 m

Since length and breadth are equal, therefore, park A is square in shape.

∴ The perimeter of Park A = 4 * side = 4 * 30 = 120 m

For Park B:

Length = 75 m

Breadth = 75 m

Similarly, the length and breadth are equal, therefore, park B is also square in shape.

∴ The perimeter of Park B = 4 * side = 4 * 75 = 300 m

Thus, we can conclude that as the perimeter of park B is more than park A, so Vijay had walked more distance.

Case (b): Which park has greater area?

Area of park A = side² = 30² = 900 m²

And,

Area of park B = side² = 75² = 5625 m²

Thus, we can conclude that the park B has a greater area than park A.

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Answer 2

Vijay had walked more distance then Ajay and Area of $Park\ B$ is more then $Park\ A$.

Step-by-step explanation:

Given,

There are two parks $A\ and\ B$

Ajay walks around $Park\ A$ with $30\ m$ length and $30\ m$ width.

Vijay walks around $Park\ B$ with $75\ m$ length and $75\ m$ width.  

In $Park\ A$,

Length and width are equal.

So, $Park\ A$ is a square.

So, Perimeter of $Park\ A$ is $(4\times 30)=120\ m$

And In $Park\ B$,

Length and width are equal.

So, $Park\ B$ is a square.

So, Perimeter of $Park\ B$ is $(4\times 75)=300\ m$

∴ Perimeter of $Park\ B$ is more then $Park\ A$.

∴ Vijay had walked more distance then Ajay.

Area of $Park\ A=30^{2}=900\ m^{2}$

And Area of $Park\ B=75^{2}=5625\ m^{2}$

∴ Area of $Park\ B$ is more then $Park\ A$.