Question

1. There are x4+57x+15 pens to be distributed in a class of x2+4x+2 students. Each student get the maximum possible number of pens. Find the number of pens received by each student and the number of pens left undistributed.​

Answer 1

Step-by-step explanation:

number of pens =

x4 + 57x + 15

number of students =

x2 + 4x + 2

each student will get maximum pens =>

x2 + 4x + 2 ) x4 + 57x + 15 ( x2 - 4x + 14

x4 + 4x3 + 2x2

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-4x3 - 2x2 + 57x

-4x3 - 16x2 - 8x

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+ 14x2 + 65x + 15

+ 14x2 + 56x + 28

****************************

9x - 13

number of pen received by each student =>

x2 - 4x + 14

number of pen left undistributed => 9x - 13

Answer 2

Step-by-step explanation:

There are x4+57x+15 pens to be distributed in a class of x2+4x+2 students. Each student get the maximum possible number of pens. Find the number of pens received by each student and the number of pens left undistributed.