Question

1
There is a certain four digit number whose fourth digit is twise the first digit. Thiird digit is three more than second digit Sum of the first
and fourth digits twise the third number What was that number?​

Answer 1

$\huge\bold{HELLO\:MATE}$

The numbers formed can be 2034 and 4368

Step-by-step explanation:

According to first condition,

Fourth digit is twice the first digit

So,

Since digit will be a single digit so choices for first digit = 1, 2, 3, 4

( 5* 2 = 10 which will be a two digit number and we need to fill a single space )

Hence fourth digit can be 1 * 2, 2 * 2, 3 * 2, 4 * 2

= 2, 4, 6, 8

now,

As per third condition, sum of the first and fourth digits is twice the third number

So, possible options are :

( 2, 4 ) = 2 + 4 = 6

( 2, 4 ) = 2 + 4 = 6( 4, 8 ) = 4 + 8 = 12

( 1, 2) and ( 3, 6 ) are not possible options since their sum is an odd number and in that case third digit will be a decimal number that is not possible

Now,

If we take ( 2, 4 ) as a pair then third digit will be 6 / 2 = 3

Similarly for ( 4, 8 ) as a pair then third digit will be 12 / 2 = 6

According to second condition,

third digit is three more than second digit.

So, if third digit is 3, second digit will be 0

if third digit is 6 , second digit will be 3

Hence,

The numbers formed can be 2034 and 4368