Question

1. Three angles of a triangle are in the ratio of 3:4:5. Find the measure of each of the three angles​

Answer 1

Answer:

$\huge\mathbb{Statements-}$

Let the angles be=3x,4x,5x

$\huge\mathbb{Solution -}$

3x+4x+5x= 180(sum of all the angles of a triangle =180°)

= 12x= 180°

= x=180÷12

= x=15°

So,

3x=45°

4x=60°

5x= 75°

Answer 2

Answer:

45,60,75

Step-by-step explanation:

take x in the middle

3:4:5 is 3x,4x,5x

the sum of the angles in a triangle is 180

so 3x+4x+5x=180°

12x=180°

x=15

3x=3×15

45

4x=4×15

60

5x=5×15

75

the angles are 45,60 ,75

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