1) Three bells ring simultaneously at 11:00 am. They ring at regular intervals of 20min, 30min and 40 min respectively. Find the time when all the three will ring together again.
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Answer:
Required time = LCM of 20 30 and 40
= 2 x 2 x 2 x 3 x 5 = 120
120 min = 2 hours
Thus, the bell will ring simultaneously after 2 hours = 1:00 pm
Step-by-step explanation:
Answered by
0
Answer:
Required time=LCM of 20,30and 40
=2×2×2×3×5=120
120 min =2 hours
This ,the bell will ring simultaneously after 2 hours = 1.00 pm
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