Question

1. Three resistors of resistances 2 ohm, 3 ohm and 5 ohm connected in series with 5V Potential difference.Current flows in the circuit will be?

Answer 1

Answer:

0.5 amperes

Explanation:

Given :

• 2 ohms, 3 ohms and 5 ohms are connected in series
• Potential difference is equal to 5 volts

To find :

• Current flown across the circuit

Equivalent resistance = 2+3+5

Equivalent resistance =5+5

Equivalent resistance = 10 ohms

Using ohms law :

V=IR

5=I×10

I=5/10

I=0.5 Amperes

The current flowing through the circuit is 0.5 amperes

Answer 2

Three resistors of resistance 2ohm, 3ohm and 5ohm are connected in series.

Let's denote the 2 ohm resistor by R1, 3 ohm resistor by R2 and 5 ohm resistor by R3, which are connected in series with 5V Potential difference as shown below:

---------| R1 |-------| R2 |-------| R3|----------

---------------------| V = 5V |---------------------

For series combination:

Rs = R1 + R2+ R3

For parallel combination:

1/Rp = 1/R1 + 1/R2 + 1/R3

As given in question, they are connected in series. So,

Rs = R1 + R2 + R3

Substitute the known in the above formula,

→ Rs = (2 + 3 + 5) ohm

→ Rs = 10 ohm

Therefore, the resistance of all the three resistors is 10 ohm.

From ohm's law we can say that,

V = IR

Here, V = Potential difference, I = Current and R = Resistance

Substitute value of V = 5V and R = 10 ohm in above formula,

→ 5 = I × 10

→ 5/10 = I

→ 0.5 = I

As, all the resistors are connected in series and in series current is same. So, the current flowing in the circuit is 0.5 A.