Question

1.three resistors of resistence 4 ohm,6 ohm and 12 ohm are given to you.a)what is the highest resistence that you can get using all of them?b) what is the lowest resistence that can be obtained using 6 ohm and 12 ohm resistors?​

Answer 1

a). Connecting them all in series would give us the highest resistance.

${R}_{eff}\:=\:{R}_{1}\:+\:{R}_{2}\:+\:{R}_{3}$

${R}_{eff}$ = 22Ω

b). Connecting these two resistances in parallel would give us lowest resistance.

1/R = 1/6 + 1/12

1/R = 2+1/12

1/R = 3/12

R = 4Ω

Answer 2

Given :-

Three resistors of resistence 4 ohm,6 ohm and 12 ohm are given to you.

To Find :-

Highest resistance

Lowest resistance

Solution :-

In case of highest resistance

Rn = R1 + R2 + R3

i.e they are connected in series

Rn = 4 + 6 + 12

Rn = 10 + 12

Rn = 22 Ω

In case of lowest resistance

If we will connect 6 Ω and 12 Ω in parallel. Then,

1/Rn = 1/R1 + 1/R2

1/Rn = 1/6 + 1/12

1/Rn = 2 + 1/12

1/Rn = 3/12

1/Rn = 1/4

Rn × 1 = 1 × 4

Rn = 4 Ω