Question

1 to 9 opposite numbers in maths​

Answer 1

Answer

-2,-3,-4,-5,-6,-7,-8,-9

Answer 2

Answer:

Opposite numbers of 1,2,3,4,5,6,7,8,9 are (-1),(-2),(-3),(-4),(-5),(-6),(-7),(-8),(-9) respectively

Step-by-step explanation:

Here given numbers are 1 to 9.

We know,

If p is a number then opposite number of p will be (-p).

So according to rule,

opposite numbers of 1,2,3,4,5,6,7,8,9 are (-1),(-2),(-3),(-4),(-5),(-6),(-7),(-8),(-9) respectively.

This is a problem of numbers part of Mathematics.

Some important Mathematics formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Two more important Mathematics problem:

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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