Math, asked by Priodey, 8 months ago

1. To do a certain work, A and B work on alternate days,
with B beginning the work on the first day. A can fin-
ish the work alone in 48 days. If the work gets com-
pleted in 11 days, then B alone can finish 4 times
the same work in?​

Answers

Answered by suskumari135
1

B does 4 times of the work in 27 days

Step-by-step explanation:

A and B worked for 16/3 and 6 days

A' s one day work = 1/48

As  16/3 days work = 1/9

1 = 1/9 + 6/days taken by B to complete the work alone

So, here days taken by B to complete the work alone = a

8/9 = 6/a

a = 27/4

Therefore,

Days to complete the 4 times of that work = 4 x 27/4  = 27 days

Hence, B does 4 times of the work in 27 days.

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