Question

1. To verify that the sum of the angles in a triangle is 180 degree.
2. Area of a triangle.
3. Mid point theorem.
4. Cyclic quadrilateral
Note- Do this maths activities in your activity copy.​

Answer 1

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Answer 2

Step-by-step explanation:

Given : ABCD is a cyclic quadrilateral of a circle with centre at O.

To prove : ∠BAD+∠BCD=180o

                  ∠ABC+∠ADC=180o

Chord AB

∠5=∠8...(1)   [Angle in same segment are equal]

Chord BC 

∠1=∠6...(2)   [Angle in same segment are equal]

Chord CD 

∠2=∠4...(3)   [Angle in same segment are equal]

Chord AD 

∠7=∠3...(4)   [Angle in same segment are equal]

By angle sum property of qudrilateral

∠A+∠B+∠C+∠D=360o

∠1+∠2+∠3+∠4+∠7+∠8+∠5+∠6=360o

(∠1+∠2+∠7+∠8)+(∠3+∠4+∠5+∠6)=360o

(∠1+∠2+∠7+∠8)+(∠7+∠2+∠8+∠1)=360o          [From (1), (2) ,(3) and (4)]

2(∠1+∠2+∠7+∠8)=360o

∠1+∠2+∠7+∠8=180o

(∠1