Question

1.
Total energy of electron in the nth orbit of He+ ion is
1) 13.6/n2
(2)-13.6/n2
(3) -27.2/n2
(4) -54.4/n2​

Answer 1

Answer:

13.6/n2 iss the answer for the question

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Answer 2

Total energy of electron in the nth orbit of $He^+$ ion is $E_n=\frac{-54.4}{n^2}$

Explanation:

Energy of the nth orbit of hydrogen and hydrogen like ions by Bohr was given by:

$E_n=R_H\times \frac{Z^2}{n^2}eV$  (1)

where,

$E_n$ = energy of nth orbit

$R_H$ = Rydberg constant

n = number of orbit

Z = atomic number = 2 ( for Helium)

Energy of the first shell(n=1) in hydrogen atom:

Z = 1

$-13.6eV=R_H\times \frac{1^2}{1^2}$

$R_H=-13.6eV$

Putting the value of $R_H$ in (1)

$E_n=-13.6\times \frac{2^2}{n^2}eV$

$E_n=\frac{-54.4}{n^2}$

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