Question

(1)total resistance of the electric circuit
(2)reading of ammeter A in the circuit​

Answer 1

Answer:

1) resistance 1/R=(1/13)+(1/44)

1/R=(44+13)/572

R=572/57=10.03

in series=10.03+2=12.03

total resistance is =12.03ohm

2) reading of Ammeter is I=V/R

I=6/12.03

I=0.49ampere

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Answer 2

Answer:

There is no resistance on the middle wire,so both ends of wire are at same potential.

this circuit can be rearranged as shown.

Total resistance =28/3 +2=34/3