Question

1 train 190 meter lambe pul ko 50 sec me paar karti hai aur 1 aadmi jo saman disha me 1.2 me/sec ki gati se chalta hai use 24 sec me paar karti hai train ki length hai

Answer 1

pool ki lambae = 190m

mana ki, train ki lambae = x

train ko pool par Karne me laga samay = 50 sec

train ki gati, y = (x + 190)/50 ......(1)

ab, ek adami Jo saman disha me 1.2 m/s ki gati se chalta hai train ko 24sec me par Kar leta hai.

atah, 24sec = (x)/(y - 1.2)

24 = (x)/{(x + 190)/50 - 1.2} [ samikaran (1) se ]

24 =50x/(x + 190 - 60)

24 = 50x/(x + 130)

24x + 24 × 130 = 50x

or, 26x = 24 × 130

or, x = 24 × 5 = 120m

atah, train ki lambae = 120m

Answer 2

Answer:

1 train 190 meter lambe pul ko 50 sec me paar karti hai aur 1 aadmi jo saman disha me 1.2 me/sec ki gati se chalta hai use 24 sec me paar karti hai train ki length hai - 120  m

Step-by-step explanation:

Pul ki lambai = 190 m

train ki lambai = T m

50 sec mein doori  = 190 + T m

Train ki gati = (190+T)/50

aadmi ki gati = 1.2 m/sec

doori 24 sec mein = 24 * 1.2 = 28.8 m

24 sec mein train ki doori = 28.8 + T

24 ( train ki gati) = 28.8 + T

=> 24( (190+T)/50)  = 28.8 + T

=> 24 * 190   + 24 T = 28.8 * 50  + 50T

=> 4560 - 1440 = 50T - 24T

=> 26T = 3120

=> T = 120

Train ki lambai = 120 m