1 Triangle ABC has vertices A(-2,-5),B(-7,5),andC(1,1).AD is a median. The gradient
of AD is
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Asked on December 26, 2019 by
Vignesh Itty
If the coordinates of the vertices of the triangle ABC be (−1,6),(−3,−9), and (5,−8) respectively, then the equation of the median through C is
A
13x−14y−47=0
B
13x−14y+47=0
C
13x+14y+47=0
D
13x+14y−47=0
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ANSWER
Let the Median be CD
Point of D is (x,y)
Now,
x=
2
−3−1
,x=−2 and y=
2
6−9
=−
2
3
Slope of CD is,
=
5+2
8−
2
3
=
14
13
Equation:
CD=y+8=
14
13
(x−5)
So the equation of Median,
13x−14y−47=0
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